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Problem Solving/PROGRAMMERS

[python]ํ”„๋กœ๊ทธ๋ž˜๋จธ์Šค-์‹ ๊ณ  ๊ฒฐ๊ณผ ๋ฐ›๊ธฐ

by DevIseo 2022. 7. 7.

[ํ”„๋กœ๊ทธ๋ž˜๋จธ์Šค]์‹ ๊ณ  ๊ฒฐ๊ณผ ๋ฐ›๊ธฐ

https://school.programmers.co.kr/learn/courses/30/lessons/92334

 

ํ”„๋กœ๊ทธ๋ž˜๋จธ์Šค

์ฝ”๋“œ ์ค‘์‹ฌ์˜ ๊ฐœ๋ฐœ์ž ์ฑ„์šฉ. ์Šคํƒ ๊ธฐ๋ฐ˜์˜ ํฌ์ง€์…˜ ๋งค์นญ. ํ”„๋กœ๊ทธ๋ž˜๋จธ์Šค์˜ ๊ฐœ๋ฐœ์ž ๋งž์ถคํ˜• ํ”„๋กœํ•„์„ ๋“ฑ๋กํ•˜๊ณ , ๋‚˜์™€ ๊ธฐ์ˆ  ๊ถํ•ฉ์ด ์ž˜ ๋งž๋Š” ๊ธฐ์—…๋“ค์„ ๋งค์นญ ๋ฐ›์œผ์„ธ์š”.

programmers.co.kr

def solution(id_list, report, k):
	#๋‹ต ์ถœ๋ ฅ์„ ์œ„ํ•ด id_list๋งŒํผ 0์œผ๋กœ ์ดˆ๊ธฐํ™”ํ•œ ๋ฆฌ์ŠคํŠธ ์ƒ์„ฑ
    answer = [0]*len(id_list)
    #id_list์˜ ๊ฐ’์„ ํ‚ค๊ฐ’์œผ๋กœ ํ•˜๋Š” ๋”•์…”๋„ˆ๋ฆฌ ์ƒ์„ฑ
    report_dic={x:0 for x in id_list}
    
    #์ค‘๋ณต๋ฐฉ์ง€๋ฅผ ์œ„ํ•ด set()
    for r in set(report):
    	#์‹ ๊ณ  ๋‹นํ•œ ์ˆ˜ ์ฒดํฌํ•ด์ฃผ๊ธฐ
        report_dic[r.split()[1]]+=1
    
    for r in set(report):
    	#์‹ ๊ณ ๋‹นํ•œ ํšŸ์ˆ˜๊ฐ€ ์ •์ง€๊ธฐ์ค€ ํšŸ์ˆ˜ ์ด์ƒ์ด๋ฉด
        if report_dic[r.split()[1]]>=k:
        	#index()๋ฅผ ์‚ฌ์šฉํ•ด ์ˆœ์„œ์— ๋งž๊ฒŒ answer์— ์ฒดํฌ
            answer[id_list.index(r.split()[0])]+=1
            
    return answer

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