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Problem Solving/BAEKJOON

[baekjoon]python #9095 1, 2, 3 ๋”ํ•˜๊ธฐ

by DevIseo 2023. 1. 11.

[baekjoon]python #9095 1, 2, 3 ๋”ํ•˜๊ธฐ

https://www.acmicpc.net/problem/9095

 

9095๋ฒˆ: 1, 2, 3 ๋”ํ•˜๊ธฐ

๊ฐ ํ…Œ์ŠคํŠธ ์ผ€์ด์Šค๋งˆ๋‹ค, n์„ 1, 2, 3์˜ ํ•ฉ์œผ๋กœ ๋‚˜ํƒ€๋‚ด๋Š” ๋ฐฉ๋ฒ•์˜ ์ˆ˜๋ฅผ ์ถœ๋ ฅํ•œ๋‹ค.

www.acmicpc.net

 

import sys
input = sys.stdin.readline

# n์€ ์–‘์ˆ˜์ด๋ฉฐ 11๋ณด๋‹ค ์ž‘์Œ
dp=[0]*11 # ๊ฐ ๊ฐฏ์ˆ˜๋ฅผ ์ €์žฅ
dp[1]=1 # 1
dp[2]=2 # 1+1,2
dp[3]=4 # 1+1+1, 1+2, 2+1, 3

# dp[4] => dp[1]+3, dp[2]+2, dp[3]+1
for i in range(4,11):
    dp[i]=dp[i-3]+dp[i-2]+dp[i-1]

T = int(input())
for _ in range(T):
    n=int(input())
    print(dp[n])

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